https://programmers.co.kr/learn/courses/30/lessons/49191
Code
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from collections import defaultdict
from queue import deque
# w - i
def bfs(graph, src):
visited = []
q = deque([src])
while q:
v = q.popleft()
if v not in visited:
visited.append(v)
q += graph[v] - set(visited)
return visited
def solution(n, results):
answer = 0
graph = {v: set() for v in range(1, n+1)}
for v1, v2 in results:
graph[v1].add(v2)
visited = {}
for v in graph:
visited[v] = bfs(graph, v)
graph = {v: set() for v in range(1, n+1)}
for v1, v2 in results:
graph[v2].add(v1)
inv_visited = {}
for v in graph:
inv_visited[v] = bfs(graph, v)
answer = 0
for v in graph:
n_knowns = len(set(visited[v] + inv_visited[v]))
if n_knowns == n:
answer += 1
return answer
Complexity
$O(|V||E|)$
- $V$ =
vertices
- $E$ =
edges
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