https://programmers.co.kr/learn/courses/30/lessons/42628
Code
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
from heapq import heappush, heappop
def solution(arguments):
max_heap = []
min_heap = []
for arg in arguments:
if arg == "D 1":
if max_heap != []:
heappop(max_heap)
if max_heap == [] or -max_heap[0] < min_heap[0]:
min_heap = []
max_heap = []
elif arg == "D -1":
if min_heap != []:
heappop(min_heap)
if min_heap == [] or -max_heap[0] < min_heap[0]:
max_heap = []
min_heap = []
else:
num = int(arg[2:])
heappush(max_heap, -num)
heappush(min_heap, num)
if min_heap == []:
return [0, 0]
return [-heappop(max_heap), heappop(min_heap)]
Complexity
PREVIOUSEtc